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Science Swali

question: a bullet of mass 10g moving with velocity of 400 m/s gets embedded in a freely suspended wooden block of mass 900g.What is the velocity acquired kwa the block?

the first person who gives the right answer with reasons would get 100 heshima and the others would get 40 heshima for participating! so good luck!
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6 hours!! this swali would get closed.
fightxd posted zaidi ya mwaka mmoja uliopita
 fightxd posted zaidi ya mwaka mmoja uliopita
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Science Majibu

demi382 said:
answer:4.4m/s
reason: let the final velocity of the bullet embedded in it be v
according to the law of conservation of momentum,
total momentum before collision = total momentum after collision
= 0.001* 400+0.9*0/0.001 + 0.9 = 4/0.91 = 400/91 = 4.4 m/s
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posted zaidi ya mwaka mmoja uliopita 
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correct answer but i can't belive that no one answered than wewe , any way congratulations!
fightxd posted zaidi ya mwaka mmoja uliopita
bahu said:
mass of bullet= 10 g = 0.01 kg
velocity of bullet=400 m/s
mass of wooden box= 900 g =0.9 kg
velocity of wooden block= ?

formula= Mb 1*Vb 1=Mb 2*Vb 2
0.01*400=0.9*Vb2
=0.01*400/0.9=4.4444444 m/s
ans=4.4 m/s
select as best answer
posted zaidi ya mwaka mmoja uliopita 
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